(x^2-9)(x^2-5x+4)=0

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Solution for (x^2-9)(x^2-5x+4)=0 equation: 


Simplifying
(x2 + -9)(x2 + -5x + 4) = 0

Reorder the terms:
(-9 + x2)(x2 + -5x + 4) = 0

Reorder the terms:
(-9 + x2)(4 + -5x + x2) = 0

Multiply (-9 + x2) * (4 + -5x + x2)
(-9(4 + -5x + x2) + x2(4 + -5x + x2)) = 0
((4 * -9 + -5x * -9 + x2 * -9) + x2(4 + -5x + x2)) = 0
((-36 + 45x + -9x2) + x2(4 + -5x + x2)) = 0
(-36 + 45x + -9x2 + (4 * x2 + -5x * x2 + x2 * x2)) = 0
(-36 + 45x + -9x2 + (4x2 + -5x3 + x4)) = 0

Combine like terms: -9x2 + 4x2 = -5x2
(-36 + 45x + -5x2 + -5x3 + x4) = 0

Solving
-36 + 45x + -5x2 + -5x3 + x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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